Question

Let the function f be defined by f(x)=x^2 + 18. If m is a positive number such that f(2m)=2f(m), what is the value of m?

Answer 1

f(x)=x^2 + 18

f(2m)=(2m)^2 + 18

f(2m) = 4m^2 + 18

Answer 2

f(x)=x^2 + 18

2*f(m)=2*(m^2 + 18)

2*f(m)=2m^2 + 36

Answer 3

f(2m)=2f(m)

4m^2 + 18 = 2m^2 + 36

keep going to solve for m

Answer 4

haha thank you! that really helped explain how to do it very well!

Answer 5

you're welcome

Answer 6

M would equal 3?

Answer 7

yep

Answer 8

okay I think I understand how to do this now.... thank you again!

Answer 9

np