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Solve the inequality: x(x-4)^2 (x-9)^3 > 0
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forget the \((x-4)^2\) term since it is always positive unless\(x=4\) in which case it is 0
and \((x-9)^3\) has the same sign of \(x-9\)
so you can start by solving \[x(x-9)>0\]
why can you disregard the cube in x(x-9)
because \(x^3>0\iff x>0\) and similarly \((x-9)^3>0\iff x-9>0\)
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the cube of a number has the same sign as the number
well my teacher wants me to solve it by changing the inequality to an = sign
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