find the vertex of the parabola f(x)=x^2-4x-2
complete the squares of RHS
this is the formula: x = -b / (2a) if you plug x into your formula, you'll find the y coordinate
y= f(x)=x^2-4x-2 y=x^2-4x-2 y=f(x)=x^2-4x+4 -6 y=(x-2)^2 -6 y+6=(x-2)^2 vertex is 2,-6
never done these kind of equations and im lost when you you put up formulas i learn better by seeing a problem worked out but i do like to try to help in the formation of the answer
ok, you're -b = 4. 2a = 2. 4/2 = 2, so x = 2. Now plug that 2 back into the function you just posted.
so would f(x)=-6
it wants the answer as a ordered pair so would the pair be (2,-6)?
yes, that is it. exactly :)
its just a simple formula, do many problems.
ty odd for walking threw that with me im a right brain person i have to see it a few times to understand it but i also dont just want the answers handed to me i like to try to learn by doing some of the work to
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