Question

What are the x– and y–intercepts of the quadratic equation y = (x – 3)2 – 25? Identify the x–intercepts by graphing the quadratic equation.

x–intercepts: (–2, 0) and (8, 0)
y–intercept: (0, –16)

x–intercepts: (2, 0) and (–8, 0)
y–intercept: (0, –16)

x–intercepts: (–2, 0) and (8, 0)
y–intercept: (0, –25)

x–intercepts: (2, 0) and (–8, 0)
y–intercept: (0, –25)

Answer 1

@RadEn @rebeccaskell94

Answer 2

@nubeer

Answer 3

first choice right ?

Answer 4

first, x-intercept when y=0,
so, (x-3)^2 - 25 = 0
(x-3)^2 - 5^2 = 0
(x-3+5)(x-3-5) = 0
(x+2)(x-8) = 0
for the zeroes, take each factor be zero :
x+2=0 or x-8=0
x=-2 or x=8
thus, x-intercepts = {(-2,0),(8,0}

Answer 5

then y-intercept when x=0
so, y = (x-3)^2 - 25
y = (0-3)^2 - 25
y = 9 - 25
y = -16
thus, y-intercept = (0,-16)