Question

10 < –3x + 1

Answer 1

\[10<-3x+1\]
Subtract both sides by 1, what would you get? @ahoward79

Answer 2

9 < -3x

Answer 3

Good, now divide both sides by 3

Answer 4

you mean -3?

Answer 5

We can do that also but let's divide by 3

Answer 6

Ok, 3.

Answer 7

What do you get now?

Answer 8

3

Answer 9

\[9<-3x\]
Divide both sides by 3
\[\frac 9 3< \frac{-3x}{3}\]
What would you get?

Answer 10

3 < x

Answer 11

Note that there is a minus sign, you can't ignore it
\[3<-x\]

Answer 12

Do you get this?

Answer 13

Can we divide by -3 instead?

Answer 14

Then we would get -3 > x

Answer 15

Yes we can :)
I'll explain you this way, we have
\[3<-x\]
Now multiply both sides by -1, the sign of inequality will change
\[-3>x\]

Answer 16

Do you get it?

Answer 17

Yes, Thank you