Two rectangles are similar. Rectangle ABCD has a length of 5 in and a width of 10 in. Rectangle ABCD is dilated by a scale factor of 4 to form rectangle FGHJ. Answer these questions using the information provided: 1. How is the area affected by the dilation? 2. How is the perimeter affected by the dilation?
to get the length and the width of rectangle of FGHJ, just multiply by 4 from the length and the width of rectangle ABCD. so, l = 4 * 5 = 20 w = 4 * 10 = 40 now, to get area use the formula : area = length * width = 20 * 40 = .... in
Thanks; let me read your reply.
It might take a few mins,ok?
60 in,yes?
for perimeter of rectangle FGHJ, use the formula : perimeter = 2(l+w) = 2(20+40) = 2 * 60 = ... in
yes, that's right sorry, the unit for area must be in squared not in :)
ok, thank u! so, how should I state my answer?
You can call me '123', by the way.
oppss.. my eyes still want to bed, @123 :) area = 20 * 40 = 80 in^2 not 60 (sorry) perimeter = 2(20+40) = 2(60) = 120 in
lol. :D
opss.. 20 * 40 = 800 not 80 my stupid --"
nope. so, what should i write for number 1?
800 in^2
oK. But 1 is asking how the area was affected by the dilation.
@AriPotta
it can be : area = 16 times of the area of before do dilated
Oh,ok. Let me write that down .
or '16 times the original area'?
yes
4^2
Ok, thx
i told you that trick before, enchilada
I'm forgetful. SORRY. HAHHAHAHAHA
for area, you square the amount of times it changed. like, if the scale factor is 3, 3^2 = 9. so the area would be 9 times greater
Oh. okay.
if you're doing volume, you cube it
So the answer would be is 16 times larger than before?
yea, 16 times the original
Oh, I GET IT! I THINK. THANKS!
The perimeter is.
the perimeter would be 4 times greater
|dw:1360977934911:dw|
Is that a good drawing?
x is the scale factor. perimeter: x^1, area: x^2, volume: x^3
thanks. i get it, volume is cubed, area is squared. so the perimeter is .. um..
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