Question

Plzz help me

How would you write the following expression as a sum or difference?
log(3√2-x/3x)

A.1/3(log(2-x)+log3x)
B. 1/3log(2-x)-log3x
C. 1/3log(2-x)-logx
D. 1/3log(2-x)+log3x

Answer 1

this is a review for a test

Answer 2

\[\log\left(\frac{\sqrt[3]{2-x}}{3x}\right)\]?

Answer 3

yes
exactly

Answer 4

or
\[\log\left(\sqrt[3]{\frac{2-x}{3x}}\right)\]

Answer 5

how did you write it like that

Answer 6

magic

Answer 7

the first one

Answer 8

then start with
\[\log(\sqrt[3]{2-x})-\log(3x)\]

Answer 9

then go to
\[\frac{1}{3}\log(2-x)-\log(3x)\]

Answer 10

Ahh i see

Answer 11

do u mind helping me with one more question?

Answer 12

sure and btw i am writing it in
\[\LaTeX\]