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OpenStudy (vortish):
find the term that should be added to the expression to form a perfect square trinomial. Write the perfect square trinomial in factored form
x^2+5x
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jimthompson5910 (jim_thompson5910):
In general
to make x^2 + bx a perfect square, you add on (b/2)^2 = (b^2)/4
jimthompson5910 (jim_thompson5910):
That will give you x^2 + bx + (b^2)/4 which will factor to (x+b/2)^2
OpenStudy (vortish):
Mr jim that is so confusing to me can you break this down some so i understand it
jimthompson5910 (jim_thompson5910):
b = ??? in this case
OpenStudy (vortish):
yes please
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jimthompson5910 (jim_thompson5910):
what is the value of b in this case
OpenStudy (vortish):
would that be five
jimthompson5910 (jim_thompson5910):
so (b/2)^2 = (5/2)^2 = 25/4
jimthompson5910 (jim_thompson5910):
which means this is the number you add on to make x^2 + 5x a perfect square
OpenStudy (vortish):
so the entire formula would be X^2+5x+25/4
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jimthompson5910 (jim_thompson5910):
yes that's a perfect square
jimthompson5910 (jim_thompson5910):
which factors to....?
OpenStudy (vortish):
i know that sense five is a general number that is in the whole equation
jimthompson5910 (jim_thompson5910):
x^2 + bx + (b^2)/4 factors to (x+b/2)^2
b = 5,
so
x^2+5x+25/4 factors to (x+5/2)^2
OpenStudy (vortish):
ok that makes sense Mr Thompson thank you so much for your time and expertise
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jimthompson5910 (jim_thompson5910):
sure thing
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