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factor a^3-3+3a^2-a I think the answer is (a-1)(a+1)(a+3)
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help @Susan9419 please
you can check by using the factor theorem let a = 1 a = -1 and a = -3 and substitute if the solution to each is zero then you have a factor here is the 1st one.. well find f(1) = (1)^3 + 3(1)^2 - 1 - 3 = 0 so (a - 1) is a factor repeat the process to check your other factors.
f(-1)= (-1)^3+3(-1)^2-1-3 is that how u do it
so f(-1) = -1 + 3 - (-1) - 3 = 0 so (a + 1) is a factor just watch the signs...
f(1)=(1)^3+3(1)^2-2-3
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so am I right or rong
help me @goformit100
you are correct...
thank u will u help me again
post the question in the normal way and I'll look at it
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