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use general power rule to find the derivative of \[(2x-3)x ^{3/2}\]
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are you taking calc too, i think i might know how to do this one,what chapter is it?
Yes I am. Still having trouble with derivatives though. If you know how to do it I'd love to know. In my book it's chapter 3 section 8
It Can be done by using Product Rule. And the answer is \[2x^{\frac{ 3 }{2}}+(2x-3)\frac{ 3 }{2}\sqrt{x}\]
yea that's what i got but does that simplify further into \[\frac{ \sqrt{x} }{ 2 }(10x-9)\] because that's the answer in the back of my book
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