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using L’Hôpital’s Rule evaluate the limit lim x→1 2x^2-x-3/x+1 (fan and medal)
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Do you mean as x goes to -1 ?: \[\frac{2x^{2}-x-3}{x+1}\]
yes sorry about that @BenjaminEE
Well since we can't evaluate at -1 when derive the denominator and the nominator. (4x - 1 ) / 1 Now we evaluate this at -1 (4*(-1) - 1) / 1 = -5 / 1 = -5 :)
@BenjaminEE thank you (: can you help me with another question similar to this one please?
I can try. But please make a new thread =) It's easier to read.
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okay (:
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