The area of a rectangle is x2 - 2x - 15 and the length of the rectangle is x + 3. Find the width of the rectangle.
A. x – 5
B. x2 + 15
C. x + 5
D. (x – 2)(x + 3)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i put b?
jimthompson5910 (jim_thompson5910):
Length * Width = Area
(x+3) * (x^2 + 15) = x^2 - 2x - 15
is that last equation true for all values of x?
OpenStudy (tkhunny):
Can't be. The area is Second Degree.
\(x^{2} - 2x - 15 = SOMETHING*(x+3)\)
I'm guessing that left hand side can be factored.
OpenStudy (anonymous):
you can factor the equation and you would find the width of the rectangle
OpenStudy (anonymous):
and b its wrong
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i figured ...
OpenStudy (anonymous):
good job :)
OpenStudy (anonymous):
since i got it wrong... =*(
OpenStudy (anonymous):
c?
jimthompson5910 (jim_thompson5910):
what do you get when you expand out (x+3)(x+5)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Its wrong
OpenStudy (anonymous):
x2 - 2x - 15=(x+3)(x_ _)
on the blank you have to find the (+ or -) and a number
OpenStudy (anonymous):
@hinarauf80
OpenStudy (anonymous):
ummm -?
OpenStudy (anonymous):
a or d
Still Need Help?
Join the QuestionCove community and study together with friends!