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Choose the equation that could be used to find two consecutive odd integers whose sum is 68. n + (n + 1) = 68 n + (n + 2) = 68 n − (n + 2) = 68 n + 2n = 68
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Okay, this is trickier. The key word here is ODD
If you had a set of numbers, say: {1, 2, 3, 4, 5, 6, 7....}, then you can pick two consecutive odd numbers at random, say 5 and 7... And the second number would always be `two more than` the first. So if 5 = n then 7 = n + 2.
That's your hint.
so B
Even integers work in a similar way as well. The second integer is always two more than the first.
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oh ok thanks
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