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Mathematics 19 Online
OpenStudy (anonymous):

The hands of a clock are 4cm and 5cm long. Find the distance b/w the tips of the hands at 16.00h . . . ANSWER = 7.81cm

OpenStudy (anonymous):

what is 16.00h ??

OpenStudy (agent0smith):

4pm

OpenStudy (anonymous):

oh!

OpenStudy (anonymous):

|dw:1361086982293:dw|

OpenStudy (anonymous):

am i drawin the figure right??

OpenStudy (agent0smith):

You have a triangle, and know one of the angles and two of the side lengths. You can probably use the sine rule here. |dw:1361087082266:dw|

OpenStudy (agent0smith):

4/12 or 1/3rd, since the angle is 1/3rd of 360 degrees at 4pm. Oh you'll probably need the cosine rule actually.

OpenStudy (agent0smith):

http://www.mathsisfun.com/algebra/images/trig-cosine-law-c.gif |dw:1361087243845:dw|

OpenStudy (anonymous):

what is the formula??

OpenStudy (anonymous):

c^2=a^2+b^2-2ab. cos gamma

OpenStudy (anonymous):

is this the formula??

OpenStudy (anonymous):

what is gamma??

OpenStudy (anonymous):

1/3 ??

OpenStudy (agent0smith):

I posted it up there: http://www.mathsisfun.com/algebra/images/trig-cosine-law-c.gif

OpenStudy (anonymous):

what is the value of C ??

OpenStudy (agent0smith):

There is no gamma...

OpenStudy (agent0smith):

C is the angle. 1/3rd of a circle, or 1/3rd of 360 degrees.

OpenStudy (anonymous):

c^2=(5)^2+(4)^2-2*5*4*cos(1/3)

OpenStudy (agent0smith):

The angle is not 1/3. The angle is 1/3rd of 360 degrees.

OpenStudy (anonymous):

120 ??

OpenStudy (agent0smith):

Correct.

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