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OpenStudy (anonymous):
The hands of a clock are 4cm and 5cm long. Find the distance b/w the tips of the hands at 16.00h
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.
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ANSWER = 7.81cm
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OpenStudy (anonymous):
what is 16.00h ??
OpenStudy (agent0smith):
4pm
OpenStudy (anonymous):
oh!
OpenStudy (anonymous):
|dw:1361086982293:dw|
OpenStudy (anonymous):
am i drawin the figure right??
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OpenStudy (agent0smith):
You have a triangle, and know one of the angles and two of the side lengths. You can probably use the sine rule here. |dw:1361087082266:dw|
OpenStudy (agent0smith):
4/12 or 1/3rd, since the angle is 1/3rd of 360 degrees at 4pm.
Oh you'll probably need the cosine rule actually.
OpenStudy (anonymous):
what is the formula??
OpenStudy (anonymous):
c^2=a^2+b^2-2ab. cos gamma
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OpenStudy (anonymous):
is this the formula??
OpenStudy (anonymous):
what is gamma??
OpenStudy (anonymous):
1/3 ??
OpenStudy (anonymous):
what is the value of C ??
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OpenStudy (agent0smith):
There is no gamma...
OpenStudy (agent0smith):
C is the angle. 1/3rd of a circle, or 1/3rd of 360 degrees.
OpenStudy (anonymous):
c^2=(5)^2+(4)^2-2*5*4*cos(1/3)
OpenStudy (agent0smith):
The angle is not 1/3. The angle is 1/3rd of 360 degrees.
OpenStudy (anonymous):
120 ??
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OpenStudy (agent0smith):
Correct.
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