A 20kg block is on a frictionless ramp the makes a 26.7 degree angle with respect the horizon. We assume that gravity is oriented along the downward direction (y-axis perpendicular to the horizontal) and the height of the ramp decreases in the direction of the positive x-axis (x-axis is parallel to the horizon). (a) If the block that rests on the ramp is released 12.3m above the horizontal, then how long does it take for the block to get to the bottom of the ramp?

Question

anonymous · Answer

hmmm.. can you draw the diagram?

anonymous · Answer

Crude drawing, but this is what we are looking at.

anonymous · Answer

mgsin(26.7)=ma
sin(26.7)=12,3/distance of the body 
distance of the body=V0.t+0.5at^2

anonymous · Answer

Indeed, sir! That is what I have thus far.

anonymous · Answer

It's a question of acceleration and initial velocity.

anonymous · Answer

yea all yuo need to do is calculate acceleration.. adn then use 1d equation of motion!

anonymous · Answer

Thanks a lot, I greatly appreciate it! It was much easier than I had first thought. I understand it now.