Question

integration by parts: te^-3t dt

Answer 1

We take the derivative of \(u\) to get \(du\). (That's why we choose \(t\) for our \(u\), so it will decrease in degree as we take it's derivative).\[\large u=t \;\;\qquad \qquad dv=e^{-3t}dt\]\[\large du=? \qquad \qquad v=?\]