Question

Solve the equation.
16y^2+8y+1=0

Answer 1

Use the quadratic equation:\[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 2

Simplifying
16y2 + 8y + 1 = 0

Reorder the terms:
1 + 8y + 16y2 = 0

Solving
1 + 8y + 16y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + 4y)(1 + 4y) = 0

Subproblem 1Set the factor '(1 + 4y)' equal to zero and attempt to solve:

Simplifying
1 + 4y = 0

Solving
1 + 4y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4y = 0 + -1
4y = 0 + -1

Combine like terms: 0 + -1 = -1
4y = -1

Divide each side by '4'.
y = -0.25

Simplifying
y = -0.25
Subproblem 2Set the factor '(1 + 4y)' equal to zero and attempt to solve:

Simplifying
1 + 4y = 0

Solving
1 + 4y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4y = 0 + -1
4y = 0 + -1

Combine like terms: 0 + -1 = -1
4y = -1

Divide each side by '4'.
y = -0.25

Simplifying
y = -0.25Solutiony = {-0.25, -0.25}