Question

Write the equation of the line that passes through (-1, 4) with a slope of -1 in standard form. -x + 4y = -1 x - 4y = -1 x + y = 3 x - y = -3

Answer 1

Write the equation of the line that passes through (-1, 4) with a slope of -1 in standard form.
Choices right here?
-x + 4y = -1
x - 4y = -1
x + y = 3
x - y = -3

Answer 2

ANYONE HERE EYYYYYYYYYYYYYYYYYY!

Answer 3

EYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Answer 4

Standard Form: the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers.

Answer 5

(-1,4) is ( x1, y1) in the equation below

Slope - Point Equation of a Line
y - y1 = m ( x - x1)

y - 4 = (-1)* ( x - (-1) )
y - 4 = (-1) * (x + 1)
y - 4 = -x - 1
x + y + 1 - 4 = 0
x + y -3 = 0
And .....
Your Task --> Get the equation in standard form as defined above.

Answer 6

I just did the math its x+y=3

Answer 7

Check out this online calculator of the equation of a line given a point on the line and the slope of the line:

http://ncalculators.com/geometry/point-slope-form-calculator.htm

Answer 8

so is this not the right answer?