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What is the vertex of this quadratic function? f(x) = 2x^2 + 4x – 5
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want to solve it graphically or algebrically?
\(\textbf{HINT}\) Complete the square.
would it be (-1,-7)?
The vertex of the quadratic function \(\large f(x)=ax^2+bx+c \) occur at (h, k) where h=-b/(2a) k=f(h)
Indeed, that's another way.
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complete the square to get your equation into vertex form: \(y = a(x – h)^2 + k\) or you could do \(x=-{b\over2a}\) to find the x value of the vertex and then plug in the \(x\) into the function to get he y-value
@venom936 , yes your answer is correct
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