Question

What are the possible number of positive, negative, and complex zeros of f(x) = x^6 + x^5+ x^4 + 4x^3 - 12x^2 + 12 ?

Answer 1

Descartes' Rule of Signs tells you that there could be four positive roots, and two negative roots, and any pair of those positive and negative roots could be replaced by a pair of complex conjugates.
In actuality, that function has two positive, two negative and two complex roots, but Descartes isn't as precise as that.

Answer 2

Ok, thanks!

Answer 3

np:)