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Mathematics 7 Online
OpenStudy (dls):

The hypotenuse of a right angled riangle has its ends at the points (1,3) and (-4,1) find the eq. of legs(perp side) of the triangle

OpenStudy (shubhamsrg):

|dw:1361295116268:dw|

OpenStudy (shubhamsrg):

|dw:1361295163427:dw|

OpenStudy (shubhamsrg):

|dw:1361295185436:dw|

OpenStudy (dls):

but why did you draw a circle in this innocent question?

OpenStudy (shubhamsrg):

take any point on the circle and you'll get a new right triangle, hence infinite answers possible.

OpenStudy (dls):

lol NCERT question and a legit answer

OpenStudy (shubhamsrg):

nopes, infinite answers! >.<

OpenStudy (shubhamsrg):

@ParthKohli

OpenStudy (shubhamsrg):

with 2 fixed points, say B and C , there can be infinite A's such that ABC is right triangle.

Parth (parthkohli):

"Angle in a semicircle is 90 degrees" thm.

OpenStudy (dls):

THM?

Parth (parthkohli):

Theorem

OpenStudy (dls):

-_-

Parth (parthkohli):

Choobham bhaiya ij light!!

OpenStudy (dls):

Answer isn't ._.

Parth (parthkohli):

No he ij light :-(

OpenStudy (anonymous):

how about this: |dw:1361295609919:dw| these are the two possibilities right? so for both the sides, we know one point each through which they pass and their slopes, 0 and infinity. us the slope-point form.

OpenStudy (shubhamsrg):

Its necessary that there'll be a rectangle.

OpenStudy (shubhamsrg):

I mean not necessary *

OpenStudy (shubhamsrg):

|dw:1361295903064:dw|

OpenStudy (shubhamsrg):

With those given points as diameter, you take any point on the circumference, and voila. a right triangle! :O

OpenStudy (anonymous):

|dw:1361295920544:dw| our side doesn't remain the hypotenuse

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