Question

Choose the equation of the line passing through the point (3, -2) and parallel to y = 3x - 6.

y = 3x + 7

y = 3x - 11

y = -3x + 11

y = -3x - 12

My answer is y = 3x - 11
Am I right? :)

Answer 1

Parallel lines have equal gradients. The gradient of the first line is 3 because it's 3x. Therefore the gradient of the other line must also be 3. Then use the formula for the equation of a line form there.\[y-y1 = m(x - x1)\]So you get y - (-2) = 3 (x - 3) which expands to be y + 2 = 3x - 9. And if you move the 2 across then you get y=3x-11 so yes you are correct sir!

Answer 2

Thank you so much! :)