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Mathematics 18 Online
OpenStudy (anonymous):

See attachment.

OpenStudy (goformit100):

Its Not a mathematics Question....

OpenStudy (anonymous):

OpenStudy (anonymous):

there.

OpenStudy (goformit100):

What was that above ?

OpenStudy (anonymous):

wrong attachment,sorry.

OpenStudy (anonymous):

@nincompoop

OpenStudy (anonymous):

wut?

OpenStudy (anonymous):

@nincompoop

OpenStudy (nincompoop):

what have you figured out so far? remember that perimeter is the sum of all the length of sides

OpenStudy (anonymous):

i know. ok. so, you have to find NL?

OpenStudy (nincompoop):

you can. you learned about Pythagorean Theorem, correct?

OpenStudy (anonymous):

yes.

OpenStudy (nincompoop):

|dw:1361330357176:dw|

OpenStudy (nincompoop):

|dw:1361330436243:dw|

OpenStudy (anonymous):

3.

OpenStudy (nincompoop):

good.

OpenStudy (anonymous):

At least I can do basic subtraction.Hahahaha.

OpenStudy (nincompoop):

|dw:1361330531247:dw|

OpenStudy (anonymous):

I can see that.

OpenStudy (nincompoop):

now using the Pythagorean Theorem we have \[C= \sqrt{A^2+B^2}\]

OpenStudy (anonymous):

Ok.

OpenStudy (nincompoop):

since we used X and Y we can substitute them to A and B let X = A Y = B I want you to rewrite the formula and plug in the known values

OpenStudy (anonymous):

Ookay....Let me try...it'll take a couple minutes...

OpenStudy (anonymous):

Oh. you mean sqrt 3^2+5^2=c^2?

OpenStudy (anonymous):

\[\sqrt{3^2+5^2}= c^2\]

OpenStudy (anonymous):

?

OpenStudy (nincompoop):

we have the value of the hypotenuse, which is going to be our C C = 5 \[C= \sqrt{X^2+Y^2}\] \[5 = \sqrt{3^2+Y^2}\] can you figure out our next step?

OpenStudy (anonymous):

ok. you have to find what y is?

OpenStudy (nincompoop):

|dw:1361331178092:dw|

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