Mathematics
18 Online
OpenStudy (anonymous):
See attachment.
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OpenStudy (goformit100):
Its Not a mathematics Question....
OpenStudy (anonymous):
OpenStudy (anonymous):
there.
OpenStudy (goformit100):
What was that above ?
OpenStudy (anonymous):
wrong attachment,sorry.
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OpenStudy (anonymous):
@nincompoop
OpenStudy (anonymous):
wut?
OpenStudy (anonymous):
@nincompoop
OpenStudy (nincompoop):
what have you figured out so far?
remember that perimeter is the sum of all the length of sides
OpenStudy (anonymous):
i know. ok. so, you have to find NL?
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OpenStudy (nincompoop):
you can. you learned about Pythagorean Theorem, correct?
OpenStudy (anonymous):
yes.
OpenStudy (nincompoop):
|dw:1361330357176:dw|
OpenStudy (nincompoop):
|dw:1361330436243:dw|
OpenStudy (anonymous):
3.
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OpenStudy (nincompoop):
good.
OpenStudy (anonymous):
At least I can do basic subtraction.Hahahaha.
OpenStudy (nincompoop):
|dw:1361330531247:dw|
OpenStudy (anonymous):
I can see that.
OpenStudy (nincompoop):
now using the Pythagorean Theorem we have
\[C= \sqrt{A^2+B^2}\]
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OpenStudy (anonymous):
Ok.
OpenStudy (nincompoop):
since we used X and Y we can substitute them to A and B
let
X = A
Y = B
I want you to rewrite the formula and plug in the known values
OpenStudy (anonymous):
Ookay....Let me try...it'll take a couple minutes...
OpenStudy (anonymous):
Oh. you mean
sqrt 3^2+5^2=c^2?
OpenStudy (anonymous):
\[\sqrt{3^2+5^2}= c^2\]
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OpenStudy (anonymous):
?
OpenStudy (nincompoop):
we have the value of the hypotenuse, which is going to be our C
C = 5
\[C= \sqrt{X^2+Y^2}\]
\[5 = \sqrt{3^2+Y^2}\]
can you figure out our next step?
OpenStudy (anonymous):
ok. you have to find what y is?
OpenStudy (nincompoop):
|dw:1361331178092:dw|