y=ax^2+c with a graph that includes (0,1/3) (-3, 82?3)
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OpenStudy (anonymous):
(-3, 82/3)
OpenStudy (anonymous):
since \((0,\frac{1}{3})\) is on the graph you know \(c=\frac{1}{3}\) because that is what you get if \(x=0\)
OpenStudy (anonymous):
so you have
\[y=ax^2+\frac{1}{3}\] put \(x=-3\) and \(y=\frac{82}{3}\) and solve for \(a\)
OpenStudy (anonymous):
in other words, solve
\[\frac{82}{3}=9a+\frac{1}{3}\] for \(a\)
OpenStudy (anonymous):
3x^2+1/3
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
@satellite73 help..
OpenStudy (anonymous):
a=3
OpenStudy (nincompoop):
you can deduct 1/3 on both sides of the equation to isolate 9a
show me what you came up with
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
y=-3x^2+2/3
OpenStudy (anonymous):
@nincompoop
OpenStudy (nincompoop):
this is what satellite left us:
\[\frac{ 82 }{ 3 }=9a+\frac{ 1 }{3 }\]
OpenStudy (anonymous):
oh,
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OpenStudy (nincompoop):
deducting 1/3 on both sides of the equation will leave us
81/3 = 9a
now you just have to divide 9 on both sides of the equation so you are left with a
OpenStudy (anonymous):
y=3x^2-1/3
OpenStudy (anonymous):
@you. can you help meh?
OpenStudy (anonymous):
I'm 12 I don't know how to solve this
OpenStudy (anonymous):
oh
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OpenStudy (nincompoop):
@selenamalter now just divide 81/3 by 9 to get the value of a
\[\frac{ 81 }{ 3 }\div \frac{ 9 }{ 1 }\]
we know that 9 x 9 is 81. so, 81/9 is 9
and 9/1 = 9
therefore, a = 9
OpenStudy (nincompoop):
sorry. THEREFORE, a = 9/3
OpenStudy (nincompoop):
9/3 = 3
OpenStudy (anonymous):
okay, so
the full answer would be
OpenStudy (anonymous):
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OpenStudy (anonymous):
those are the answer options
and
D. none of these answers
OpenStudy (nincompoop):
assuming that where satellite left off is correct, then the answer would be D
I trust satellite's math skills LOL
OpenStudy (anonymous):
;)
wow, thanks :D
OpenStudy (nincompoop):
no problem gal
OpenStudy (anonymous):
i can go to bed now lol....
thank ya lad :D
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OpenStudy (nincompoop):
give satellite the medal. I didn't really do anything. I just merely showed you what he wanted you to do.