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Mathematics 16 Online
OpenStudy (anonymous):

tan225+sin240cos60

OpenStudy (anonymous):

Method without using calculator?

OpenStudy (ash2326):

@Grazes Have you studied the values of trigonometric ratios in different quadrants?

OpenStudy (anonymous):

Yes.

OpenStudy (ash2326):

what's tan 225? I'll give you a hint, write it as \(\tan(180+45)\)

OpenStudy (anonymous):

Is it 0+1 or 1?

OpenStudy (ash2326):

We know that tan is positive in third quadrant so \[\tan(180+x)=\tan x\] so \[\tan (180+45)=\tan 45\]

OpenStudy (anonymous):

My bad. I calculate tan180+tan45

OpenStudy (ash2326):

Do you get my point?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

So sin240 is equal to sin60 but it's is negative in the 3rd quadrant?

OpenStudy (anonymous):

Would it be\[1+ (-\frac{ \sqrt{3} }{ 2 }\times \frac{ 1 }{ 2 })\]

OpenStudy (ash2326):

yes , you are right :D Good work

OpenStudy (anonymous):

Thanks.

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