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tan225+sin240cos60
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Method without using calculator?
@Grazes Have you studied the values of trigonometric ratios in different quadrants?
Yes.
what's tan 225? I'll give you a hint, write it as \(\tan(180+45)\)
Is it 0+1 or 1?
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We know that tan is positive in third quadrant so \[\tan(180+x)=\tan x\] so \[\tan (180+45)=\tan 45\]
My bad. I calculate tan180+tan45
Do you get my point?
Yes.
So sin240 is equal to sin60 but it's is negative in the 3rd quadrant?
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Would it be\[1+ (-\frac{ \sqrt{3} }{ 2 }\times \frac{ 1 }{ 2 })\]
yes , you are right :D Good work
Thanks.
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