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factor 3x^2+9x+x+3.. Help?
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3x^2+9x+x+3 (3x^2+9x)+(x+3) 3x(x+3)+1(x+3) what's next?
distribute?
why do that? that will just make you go back a step and get you back to (3x^2+9x)+(x+3) again
why not factor out that common term (x+3)
Idk? that's why i'm so confused because our teacher tells us to do that.. -_-
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3x^2+9x+x+3 (3x^2+9x)+(x+3) 3x(x+3)+1(x+3) (3x+1)(x+3) ... factor out the GCF x+3
see how I went from 3x(x+3)+1(x+3) to (3x+1)(x+3) ?
yeah I understand now :) thank you!
ok great
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