A friend tosses a baseball out of his second floor window with initial velocity of 4.3m/s(42degrees below the horizontal). The ball starts from a height of 3.9m and you catch the ball 1.4m above the ground.
a) Calc the time the ball is in the air (ans. 0.48s)
b)Determine your horisontal distance from window (ans. 1.5 m)
c)Calc the speed of ball as you catch it (ans: 8.2m/s)

I dont get what 42 m below the horizontal is, can someone give me direction on how to do this?

Question

A friend tosses a baseball out of his second floor  window with initial velocity of 4.3m/s(42degrees below the horizontal). The ball starts from a height of 3.9m and you catch the ball 1.4m above the ground.
a) Calc the time the ball is in the air (ans. 0.48s)
b)Determine your horisontal distance from window (ans. 1.5 m)
c)Calc the speed of ball as you catch it (ans: 8.2m/s)

I dont get what 42 m below the horizontal is, can someone give me direction on how to do this?

anonymous · Answer

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sinbearciante · Answer

It is saying that the person tossing the ball is tossing it at an angle 42 degrees below the horizontal axis. So say you want to throw a ball straight in front of you, thats the horizontal axis. If you wanted to throw it straight down that would be 90 degrees below the horizontal axis.

anonymous · Answer

sorry i took the wrong angle.. its the other angle!

anonymous · Answer

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