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Mathematics 21 Online
OpenStudy (anonymous):

HELP PLEASE In △PQR, segment QS is an altitude.

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910 CAN YOU HELP?

jimthompson5910 (jim_thompson5910):

20/x = x/5 20*5 = x*x x^2 = 20*5 x^2 = 100 x = ???

jimthompson5910 (jim_thompson5910):

once you find x, you can find y (using the pythagorean theorem)

OpenStudy (anonymous):

[5\sqrt{10}\]?

jimthompson5910 (jim_thompson5910):

x = sqrt(100) = ??

OpenStudy (anonymous):

X=10

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

yep, now use this to find y

OpenStudy (anonymous):

y=5sqrt 10

jimthompson5910 (jim_thompson5910):

a^2 + b^2 = c^2 10^2 + 20^2 = y^2 100 + 400 = y^2 y^2 = 500 y = sqrt(500) y = ???

OpenStudy (anonymous):

50 im confused

jimthompson5910 (jim_thompson5910):

sqrt(500) = sqrt(100*5) sqrt(500) = sqrt(100)*sqrt(5) sqrt(500) = ???

OpenStudy (anonymous):

10*5

jimthompson5910 (jim_thompson5910):

sqrt(100) is what

OpenStudy (anonymous):

10

jimthompson5910 (jim_thompson5910):

so sqrt(500) = sqrt(100*5) sqrt(500) = sqrt(100)*sqrt(5) sqrt(500) = 10*sqrt(5)

jimthompson5910 (jim_thompson5910):

therefore y = sqrt(500) y = 10*sqrt(5)

OpenStudy (anonymous):

ooo

OpenStudy (anonymous):

thank you so much my teacher did it a different way i didnt understand im goin to intro duce this to her :)

jimthompson5910 (jim_thompson5910):

alright, glad I could help

OpenStudy (anonymous):

:)

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