Mathematics
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OpenStudy (anonymous):
HELP PLEASE
In △PQR, segment QS is an altitude.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910 CAN YOU HELP?
jimthompson5910 (jim_thompson5910):
20/x = x/5
20*5 = x*x
x^2 = 20*5
x^2 = 100
x = ???
jimthompson5910 (jim_thompson5910):
once you find x, you can find y (using the pythagorean theorem)
OpenStudy (anonymous):
[5\sqrt{10}\]?
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jimthompson5910 (jim_thompson5910):
x = sqrt(100) = ??
OpenStudy (anonymous):
X=10
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
yep, now use this to find y
OpenStudy (anonymous):
y=5sqrt 10
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jimthompson5910 (jim_thompson5910):
a^2 + b^2 = c^2
10^2 + 20^2 = y^2
100 + 400 = y^2
y^2 = 500
y = sqrt(500)
y = ???
OpenStudy (anonymous):
50 im confused
jimthompson5910 (jim_thompson5910):
sqrt(500) = sqrt(100*5)
sqrt(500) = sqrt(100)*sqrt(5)
sqrt(500) = ???
OpenStudy (anonymous):
10*5
jimthompson5910 (jim_thompson5910):
sqrt(100) is what
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OpenStudy (anonymous):
10
jimthompson5910 (jim_thompson5910):
so
sqrt(500) = sqrt(100*5)
sqrt(500) = sqrt(100)*sqrt(5)
sqrt(500) = 10*sqrt(5)
jimthompson5910 (jim_thompson5910):
therefore
y = sqrt(500)
y = 10*sqrt(5)
OpenStudy (anonymous):
ooo
OpenStudy (anonymous):
thank you so much my teacher did it a different way i didnt understand im goin to intro duce this to her :)
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jimthompson5910 (jim_thompson5910):
alright, glad I could help
OpenStudy (anonymous):
:)