Question

let f(x) = e^x and let R be the region bounded by the graph of f and the x axis for x < or equal to -1. Does the solid generated by revolving R about the x-axis have a finite volume? If so, find the volume. If not, show why not

Answer 1

Yes

Answer 2

is it pi/2 e^-2 ?

Answer 3

\[A=\pi (e^x)^2\]\[V=\pi \int_{-1}^{0}e^{2x}\]

Answer 4

thanks

Answer 5

I got \[\frac{\pi}{2}(1-e^{-2})\]