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Mathematics 17 Online
OpenStudy (anonymous):

limit as n approaches infinity of pi*cos(pi*n)

OpenStudy (perl):

what is cos (pi) , cos (pi*2) , cos(pi*3) ...

OpenStudy (anonymous):

1

OpenStudy (perl):

we have an alternating sequence

OpenStudy (perl):

1, -1, 1, -1, 1,....

OpenStudy (perl):

so the sequence becomes pi * (-1)^n+1 , and that doesnt converge

OpenStudy (perl):

the sequence is pi, -pi, pi , -pi, .... which oscillates

OpenStudy (anonymous):

maybe i simplified my problem incorrectly. the way this question is organized in my assignment, it must have a limit. What is the limit as n approaches infinity of 2rn*sin(pi/n) ? where n is a pos. integer and r is the value of my radius

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