Plz help! Will give medal!! Factor Completely. 48y2 + 82y – 70
You can factor \(2\) out.
ok, but then what?
2(24y+41y-35) i think is the next step
This is not enough for her i guess. she wants more.
It factors further than that, but you have to find factors of 840 that have a difference of 41 and that happens to be 56 and 15. So, you can break up your inner term to :: \[24y ^{2}+56y-15y-35\] And then factor the four terms by grouping. \[(24y ^{2}+56y) + (-15y-35)\] Then factor each expression: \[8y(3y+7) -5(3y+7)\] Then factor the common factor from each: (3y+7)(8y-5) So your complete answer with the two factored out is: 2(3y+7)(8y-5)
The 840 come from the fact that I had to multiply 24 AND 35 together to get 840. I then must find factors of 840 which have a difference of 41. I should have lead with that....lol
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