how many numbers from 1- 1000 are divisible by both 2 AND 5? Pls help!! @TrashMan914
Hint: to be "divisible by both 2 AND 5" is to be divisible by 2*5 = 10
so just list out the multiples of 10 from 1 to 1000 or you can use the idea that 10 = 10*1 20 = 10*2 30 = 10*3 ... .... 980 = 98*10 990 = 99*10 1000 = 100*10 so that will speed up the counting process
so 1000/10?
Oh i guess I should stay consistent 10 = 10*1 20 = 10*2 30 = 10*3 ... .... 980 = 10*98 990 = 10*99 1000 = 10*100
can you see how many numbers there are using that trick?
100 thanks! btw if you were to ask for the numbers from 1-1000 divisible by both 6 and 9 would you find the least common multiple of 18? the 1000/18?
yes you would find the LCM of 6 and 9, which is 18, then list out the multiples
do you have to list out the multiples or can you just do 1000/18=55.5? then get 55 as your answer?
that works as well since 55*18 = 990 and that's as high as you can go so basically 18 = 18*1 36 = 18*2 ... ... 990 = 18*55
thank you so much for your help :)
sure thing
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