Find the solution to each system by the addition (elimination) method. Check your answer for exercises 23-26.
5s+9r=6
4s-3t=15

Question

Find the solution to each system by the addition (elimination) method. Check your answer for exercises 23-26.
5s+9r=6
4s-3t=15

zzr0ck3r · Answer

s t and r?

abb0t · Answer

poop on it

anonymous · Answer

It was need my book

zzr0ck3r · Answer

say again?

zzr0ck3r · Answer

this is two equations with three unknowns

anonymous · Answer

I don't know I just put everything that was in my book on the web site

zzr0ck3r · Answer

are you sure there is a t and a r?

anonymous · Answer

sorry I miss it up it is 5s+9t=6 and 4s-3t=15. I'm sorry about that

zzr0ck3r · Answer

ok this is good:0

zzr0ck3r · Answer

5s+9t = 6
4s - 3t = 15
we want to multiply one of the equations by something so that when we add it to the other one, one variable drops, multiply the second equation by 3

zzr0ck3r · Answer

5s + 9t = 6
12s -9t = 45
now add the equations

anonymous · Answer

and its two liner equations in two variables is to add the two equations

zzr0ck3r · Answer

17s + 0 = 51
so s = 3
now use either equation to find t

zzr0ck3r · Answer

5s+9t = 6
plug in s
5(3) + 9t = 6 so t = -1
so s = 3 t = -1 is the only solution

zzr0ck3r · Answer

understand?

anonymous · Answer

not really

zzr0ck3r · Answer

what part?

anonymous · Answer

How did you get 3 for s