Find the exact value of arccos (sin (pi/6)). For full credit, explain your reasoning.
http://en.wikipedia.org/wiki/File:Unit_circle_angles_color.svg If you can print and laminate that, go for it. It's very useful. Also this: http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
if i understood the question then sin(pi/6)=1/2, arccos(1/2)=pi/3
@mathsmind so the final answer will be pi/3 right?
yes
i think everyone here knows the answer but they are trying to teach you
how should i explain the reasoning? yeahh
well as the guys said you can look at the triangle, from their you find the value of sin(pi/6). then the arccos would be the value obtained from the triangle and unit circle...
i don't know if you know arccos triangle as well, which needs a bit of explination...
let me explain this in an algabreac way,,, if theta =arccos(x) and x=sin(pi/6) then all this is saying you are dealing with the same triangle not different one by definition.. I hope this makes sense...
yeahh
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