Help needed!!!! on breaking of middle terms!!
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6k^4+39k^3+91k^2+89k+30
How to break this ^
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into this -- 6k^4+12k^3+27k^3+54k^2+37k^2+74k+15k+30

Question

Help needed!!!! on breaking of middle terms!!
.
.
6k^4+39k^3+91k^2+89k+30
How to break this ^
.
into this -->  6k^4+12k^3+27k^3+54k^2+37k^2+74k+15k+30

anonymous · Answer

hey thats simple mathematical operations

anonymous · Answer

how is it breaking??

anonymous · Answer

can you tell me the original question plz .........................maybe it'll help me to be clear

anonymous · Answer

it would take a lot of time if i tell u that question it is a mathematical induction type of question

anonymous · Answer

because the bottom one adds up and equals the top one, its okay. theres a name for this method i cant remember. its like when youre completing the square

anonymous · Answer

so how do u know to break the right terms???

anonymous · Answer

i already know it adds the top one  ..... how is it breaking thats the question??

anonymous · Answer

plzzzzzzzzzzzzzz help serious help needed 2mmorow is my test

anonymous · Answer

:( :( :(

anonymous · Answer

oh common!! where is everybody :(

anonymous · Answer

just give me the question the original one

unklerhaukus · Answer

does this help?

$$\quad 6k^4\quad\qquad+39k^3\quad\qquad+91k^2\quad\qquad+89k+30$$
$$=6k^4+(12+27)k^3+(54+37)k^2+(74+15)k+30$$
$$=6k^4+12k^3+27k^3+54k2+37k^2+74k+15k+30$$

parthkohli · Answer

But how do we exactly know that we must "break" $39$ into $27 + 12$? Doesn't it seem very trivial to break it exactly into $27 + 12$ and not anything else?

unklerhaukus · Answer

^^ i'm missing a caret

parthkohli · Answer

@unklerhaukus I found one in my pocket. Is it yours?

unklerhaukus · Answer

um,    yes. How did you get that?

parthkohli · Answer

I found it in my pocket.