Question

Compute the probability of randomly selecting a two or three from a deck of cards (52 cards)...Thanks @agent0smith...but I need more help..here is a picture of what i have

Answer 1

I am not just what to replace -P(E and F) with?

Answer 2

It's simpler than that - you're only picking one card, it's impossible to pick BOTH a 2 and 3.

There's four 2's and four 3's, so 8 total, over 52 cards total, so the probability is 8/52.

Answer 3

P of picking a 2, 3 or 4: there's four of each, so 12 total, over the 52 in the deck: 12/52

P of picking a 2 or club: there are 13 clubs, and four 2's - but one of the 2's is a club, so let's use thirteen clubs and three 2's, so fifteen total, over the 52: 15/52