how many four digit even numbers can be formed from the digits (2,4,6,7,9) if no digit is used more than once?
Lets see. To be even it has to end in an even number. So we have 4 positions where we can place numbers. Lets start from the back. _ _ _ _ 1 2 3 4 st/th/nd/rd dight 4th digit: 3 options 3rd digit: 4 options 2nd digit: 3 options 1st digit: 2 options 3*4*3*2 = 72 numbers
why are there 4 options for the 3rd digit?
Because you used one of the even digit. Since you had 5 digits to begin with now you are down one and so have 4 options since the 3rd digit can be either odd or even. The 4th digit it the only special case
omg i get it! thank you so much!! :')
are you always on this? 0.0
No, actually just found it again after several months. I was supposed to be doing my coursework too >_<
well crap x.x lmfaooo why are u helping other people then?? .-. (not complaining!)
Procrastinating essentially.
story of my life yo xD
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