Question

1. 3x(2x + 9) (1 point)
5x2 + 12x
6x + 27
12x + 27x
6x2 + 27x
2. 4w2(8w – 5) (1 point)
12w2 – 9
32w + 20w2
4w3 – w2
32w3 – 20w2
3. –5y3(11y2 – 2y3) (1 point)
–55y5 + 10y6
6y–1 – 7
55y5 – 10y3
–55y6 + 10y9
For numbers 4 – 5, factor the polynomial.

4. 12x5 – 20x4 + 16x2 (1 point)
2x(6x5 – 10x4 + 8x2)
2x2(24x7 – 40x6 – 32x4)
4x(3x4 – 10x3 + 4x)
4x2(3x3 – 5x2 + 4)
5. 5g8 + 25g5 – 20g3 (1 point)
5g(g7 + 5g4 – 4g)
10g3(0.5g5 + 2.5g3 – 2)
5g3(g5 + 5g2 – 4)
5g2(25g10 + 125g7 – 100g5)

Answer 1

Here's number one:
Look at:

\(\huge 3x(2x + 9)\)

Expanded term \(3*x\) by using associative property on \([2*x+9]\).
It becomes \([3*x*2*x] + [3*x*9]\).
Look at the 3 and 2 the.
Multiplied numerator integers
It becomes \(6*x*x+3*x*9\).
Look at 3 and 9.
Multiplied numerator integers
It becomes \(6*x*x+27*x\).
Look at the x, x.
Reduce similar several occurrences of \(x\) to \(x^2\).
It becomes \(6*x^2+27*x\).
Result:
\(6*x^2+27*x\).

Now solve two and three :3

Answer 2

ok thanks for the help

Answer 3

It's quite easy when you look at it :-).

Answer 4

that moderator douche came in here and deleted my questions

Answer 5

That's not nice to call names -.-

Answer 6

lol no need into deleting my question
when im clearly suffering from Dyscalculia

Answer 7

I suck at polynomials.
Maybe @AriPotta can help you :-).

Answer 8

well thanks

Answer 9

1. 3x(2x + 9)
6x^2 + 27x

2. 4w^2 (8w - 5)
32w^3 - 20w^2

3. -5y^3(11y^2 - 2y^3)
- 55y^5 + 10y^6

4. 12x^5 - 20x^4 + 16x^2
4x^2(3x^3 - 5x^2 + 4)

5. 5g^8 + 25g^5 - 20g^3
5g^3(g^5 + 5g^2 - 4)

Answer 10

@kelliegirl33
You can't just give answers like that...
You have to show work...

Answer 11

sorry....just trying to give a person a little break....I will do better