Question

√81x^6

This is what I got can anyone check this for me and explain?
√(9x^3)^2√x

Answer 1

Not sure where the radicals expand out to.
sqrt(81x^6)= sqrt(81)*sqrt(x^6) = 9 sqrt(x^6). Now with the sqrt(x^6) we need to be careful. If x < 0 sqrt(x^6) > 0. We need to retain that information.
So as with sqrt(x^2) we need abolute value signs.
So sqrt(81x^6)=9abs(x^3)

Answer 2

@Xavier What do you mean 9abs(x^3)
abs?

Answer 3

absolute value abs(x^3) = |x^3|

Answer 4

@Xavier
oooooh alright

Answer 5

Xavier 9√(x^3)

Answer 6

I think I went too far with my posted answer