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Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6. y + 3 = -6(x + 2) y + 2 = 6(x + 3) y - 3 = -6(x - 2) y - 2 = 6(x - 3)
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use the point-slope formula y - y1 = m(x-x1) where m = slope x1 = x coordinate of given point y1 = y coordinate of given point
ohhh okkk so is it y + 2 = 6(x + 3) @jim_thompson5910
very close, but the slope is negative, not positive
oh i don't know why i didn't see that the terms are flipped
my bad lol
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m = -6 x1 = -2 y1 = -3 y - y1 = m(x-x1) y - (-3) = -6(x-(-2)) y+3 = -6(x+2)
@jim_thompson5910 thank you so much!! :) i get it now :))
yeah there's not much to it yw
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