Stumped one this one. A piece of cake for you guys, probably haha so yeah here it is. Solve the linear system using substitution. 3x+2y=5 5x-9y=-4 Thanks. :)
find out y in terms of x or x in terms of y and substitute it`s value in the 2nd equation
Yep, and I got y=3/2x + 5/2 Plugged it into the second equation but came out with a totally wack answer.
1st part is wrong it should be y = -3/2x +5/2 you missed the - sign
Nooo, pretty sure there isn't negative in the first one. :P
3x+2y=5 2y = 5 - 3x y = 5/2 - 3/2x so it`s - sign whereas you have written y = 5/2 +3/2x which is wrong
Oh yeah, we'll I did do a negative on paper, re wrote it wrong here.
You get... 5x-9(-3/2x+5/2) = -4
yes this is right
Then I got.... 5x-27/2x-45/2=-4
no - with - cancels out so it should be 5x + 27/2x - 45/2=-4
Indeed, sorry. Then I got, 37/2x = 18 1/2 I may lose you at this part, so yeah brace yourself. :P
yes thats right and it gives you x = 1
That's correct, thanks! :-D
welcome :)
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