Question

amplitude:2
period:6pi
phase shift:1/3
y=2sin(_x-_)
how do i find the period for the equation?

Answer 1

@ashleedean12 Suppose you have
\[A\sin (\omega t+\theta)\]
\[\omega=frequency\ in\ rad/s\]
\[A=amplitude
\]
\[\theta= phase\ shift\]
Relation between period T and \(\omega\)
\[T=\frac{2 \pi}{\omega}\]
here T= 6pi so
\[6\pi=\frac{2\pi}{\omega}\]
Find \(\omega\) from this ?

Answer 2

would it be 3x?

Answer 3

or 1/3?

Answer 4

freq=2pi/period--rearrange
per=2pi/frq

Answer 5

w=1/3