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solve tanx- Sqrt of 3= 0
for 0< (greater than or equal)
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Applying algebra, by adding sqrt(3) on both sides, you get \[\huge \tan x = \sqrt{3}\]
So, what angles have a tangent of sqrt(3)
ohhhhhh thats all O_o
60 ...but im not sure what the other one is
Nice one. But given your question, I'm pretty sure you need to put it in Radians. Second... the period of tangent is pi.... that is to say, it repeats itself if you add pi (or 180 degrees) to the angle. Have fun with maths :) AGAIN: Express it in Radians :)
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pi/3 and 4pi/3 O_o?
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