Question

How do I factor 4n^2-8n+3???Please help?

Answer 1

the first coefficient is 4

the last term is 3

multiply them to get 4*3 = 12

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Now list out the possible ways to multiply to 12

12 = 1*12
12 = 2*6
12 = 3*4

12 = -1*(-12)
12 = -2*(-6)
12 = -3*(-4)


which of these pairs of factors add to -8 ?

Answer 2

-2 and 6...But I think I keep writing 8n factored wrong,I keep putting 4n^2-2-6+3...Is that part correct??

Answer 3

4n^2-8n+3

should break into

4n^2-2n - 6n+3

Answer 4

because -2 and -6

a) multiply to 12

AND

b) add to -8

Answer 5

now you factor 4n^2-2n - 6n+3 by grouping

Answer 6

4n^2-2n - 6n+3

(4n^2-2n) + (-6n+3)

2n(2n - 1) - 3(2n - 1)

What's next?

Answer 7

I egt n(4n-2)+2(3n+1),how do I get to the right answer for this part.I keep getting the same thing but its wrong.

Answer 8

do you see how I got 2n(2n - 1) - 3(2n - 1) ?

Answer 9

Not really,Could you please explain it?

Answer 10

you see how I got 4n^2-2n - 6n+3 right?

Answer 11

yeah,that part I understand.

Answer 12

ok in the next step, I grouped the terms into pairs like this

(4n^2-2n) + (-6n+3)

Answer 13

basically the first two terms get in one set of parenthesis

the next two get the next set of parenthesis

Answer 14

from there, I factored the GCF of the first group out of the first group

the GCF of 4n^2 - 2n is 2n

So I factored 2n from 4n^2 - 2n to get

4n^2 - 2n = 2n(2n - 1)

Answer 15

Then I factored -3 from -6n + 3 to get

-6n+3 = -3(2n - 1)

Answer 16

so that's how I went from

(4n^2-2n) + (-6n+3)

to

2n(2n - 1) - 3(2n - 1)

Answer 17

Ok,so the next part should look like (2n-3)(2n-1).And that would be the answer?

Answer 18

that is correct

Answer 19

Thank you very much :)

Answer 20

you can expand that out and combine like terms

you should get the original expression back again

that's one way to check the answer

Answer 21

yw