Question

1 + cos θ - 2sin^(2)θ=0

Answer 1

I would change\[\sin^2(\theta)\] to one of the cosine trig identities.

Answer 2

Which one would that be? Sin^2 x + Cos^2 x =1?
Im confused lol

Answer 3

\[\sin^2(\theta) = 1-\cos^2(x)\]
then you'll have it in the form: \[ax^2+bx+c\] and you can factor it out, solve when it's equal to zero.

Answer 4

Alright I see what you did there, let me check it out

Answer 5

Got it, thank you