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Mathematics 13 Online
OpenStudy (anonymous):

z^3+27 factor sum of two cubes

OpenStudy (anonymous):

@Compassionate

OpenStudy (anonymous):

can you please show work with this one

OpenStudy (compassionate):

I'll add the first two terms into parenthesis. (z + 3) Using the formula (a+b)*(a^2+ab+b^2) I can plug in my second set of parenthesis I know it's a sum of two cubes. So I know my terms will be descending . (z + 3)(z^2 + 3z + 9)

OpenStudy (anonymous):

so thats the answer?

OpenStudy (compassionate):

Yes

OpenStudy (anonymous):

it told me its wrong idk

OpenStudy (mathstudent55):

There is a slight error here. The first sign in the trinomial is wrong. z^3 + 27 = (z + 3)(z^2 - 3z + 9)

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