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Factorise ... (if able to pleASE include steps)
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\[3x ^{2}+5x+2\]
you can write 5x as 3x + 2x
for any quadratic \[ax^2 + bx + c \] ok... so multiply by the coefficient of the leading term by the constant 3 * 2 = 6 what are the factors of 6 that add to 5...... 2 + 3 so using this information write (ax + factor1)(ax + factor 2) ------------------------ a or \[\frac{(3x + 3)(3x + 2)}{3} \] there is a common factor in the 1st binomial that will allow you to remove a common factor with the denominator. whats left is the factorised quadratic
the method above works in every case..
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