Question

Evaluate: integral of [(1)/sqrt(-x^2-4x-3)]dx

Answer 1

dat is hard

Answer 2

can u tell me a polyhedron in an easy way

Answer 3

\[\Large \sqrt{-x^2-4x-3}=\sqrt{1-(x+2)^2}\]
you may use trigonometric substitution if you haven't recognize the integral as Arcsine or \(sin^{-1}\)

Answer 4

ohhhhhh!

Answer 5

xD wow. now i see it

Answer 6

so the answer would just be arcsin (x+2) ?

Answer 7

yup.