I need help with question b at http://fotos.fotoflexer.com/ab6708adcc65bedaa788d84fee44ea9c.jpg . Thanks. :)
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OpenStudy (anonymous):
Please help me?
OpenStudy (anonymous):
@Kitt020912
OpenStudy (anonymous):
hmm, I think its \[3\over15\] but I'm not exactly possitive.
OpenStudy (anonymous):
Hmm. Could you explain,please?
OpenStudy (anonymous):
uhm. let me read that again.
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OpenStudy (anonymous):
how did u get /31?
OpenStudy (anonymous):
I added together all of the numbers and then took the number of reds and put it over that and simply reduced it. But I'm not sure I did it right because of the way that the question was asked. Oh and @zupster 6+8+5+9+2=30 not 25.
OpenStudy (anonymous):
Thanks.
OpenStudy (anonymous):
You're welcome(: idk If I helped or not.
OpenStudy (anonymous):
I think you did:)
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OpenStudy (anonymous):
Thank you.
OpenStudy (anonymous):
No problem :D ♥
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
wait, mitt
OpenStudy (anonymous):
i have a question.
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OpenStudy (anonymous):
I still need to pee ._. lol
OpenStudy (anonymous):
do you know what it means by 'without replacing the other candy'?
OpenStudy (anonymous):
then, perhaps it's 10 over 30, which would mean that it would be 1/3
OpenStudy (anonymous):
hmmm....
OpenStudy (anonymous):
The probability of selecting red is 9 / 30. The probability of selecting red for second time is 8 / 29.
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OpenStudy (anonymous):
So what is the answer?
OpenStudy (anonymous):
8 / 29?
OpenStudy (anonymous):
No.
OpenStudy (anonymous):
Oh.
OpenStudy (anonymous):
Sorry, you're on your own.
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OpenStudy (anonymous):
Hmm.
OpenStudy (anonymous):
How is the probability the second time 8/29? you took away two candies didnt you?
OpenStudy (anonymous):
That doesnt seem right..
OpenStudy (anonymous):
No, it is asking what is the probability of selecting 2 red ones.
OpenStudy (anonymous):
On part A i got 1/90
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OpenStudy (anonymous):
maybe that has something to do w/it?
OpenStudy (anonymous):
I can doublr check this with a teacher if you want.
OpenStudy (anonymous):
Thats okay. :)
OpenStudy (anonymous):
I'm doing it anyway :P I dont want you to have the wrong answer c:
OpenStudy (anonymous):
Okay.:)
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