Question

Can anyone help me?
Find the first 4 partial sums. The answers can be left in exact form or written as 4-place decimals.

cos({n*pi}/4) for n=0 to infinity

Answer 1

for \(n=0\) you get \(\cos(0)=1\)

Answer 2

for \(n=1\) you get \(\cos(\frac{\pi}{4})=\frac{\sqrt{2}}{2}\) so second partial sum is
\[1+\frac{\sqrt{2}}{2}\]

Answer 3

for \(n=2\) you get \(\cos(\frac{\pi}{2})=0\) so third partial sum is the same as the second

Answer 4

etc

Answer 5

Awesome Thank you!

Answer 6

yw